Fora three-phase AC circuit, if the line to line voltage is known, kilowatts can be calculated from ampere using the following formula. For any three-phase AC circuit, Power kW = (â3 x V L x P.F. x I L ) / 1000. Where V L and I L are the RMS value of the applied line voltage and line current respectively and P.F. is the power factor of the load.
āļāļēāļĢāļāļģāļāļ§āļāļāđāļ§āļĒāđāļĢāļāļāļąāļāđāļāļāđāļēāļāļĩāđāđāļāđāļāļāļĨāļēāļ āļāļĢāļ°āđāļŠāđāļāļŠ I āđāļāđāļāļĄāļāđ (A) āđāļāđāļēāļāļąāļ 1,000 āđāļāđāļēāļāļāļāļāļģāļĨāļąāļ P āđāļāļŦāļāđāļ§āļĒāļāļīāđāļĨāļ§āļąāļāļāđ (āļāļīāđāļĨāļ§āļąāļāļāđ) āļŦāļēāļĢāļāđāļ§āļĒ 3 āđāļāđāļē
Fora single phase 3 HP motor at 208 volts the amperage is 18.7 amps. For a three phase 3 HP motor at 208 volts the amperage is 10.5 amps. This figure is derived at by taking the full load amps at 230 volts and adding 10%. As the voltage goes down the amperage goes up. For 200 volt motors 15% is added to the FLA of a 230 volt motor.
5kW to Amps Conversion. From our formulas follows that in order to get 5 kilowatts in amps we must know the voltage. Assumed the PF is 0.5, and supposed the voltage is
3 My new range says it needs a 40-amp circuit breaker minimum. But it also says maximum draw is 13,200 watts on 120/240, so doesn't that mean a 40-amp breaker would be inadequate? By my math, max wattage on a 40-amp circuit is 9,600, de-rated to 7,680. I'm unlikely to have the oven and all five stove segments going full burn at once, but
Well use 220 volts for our calculations. KILOVOLT-AMPERES (kVA) = VOLTS x AMPERES x POWER FACTOR x 2 1000. 220 x 4.7 x 2 = 2068 2068 x .85 = 1757.8 1757.8 / 1000 = 1.76 kW. 3. THREE-PHASE. Given: We have a very large appliance that shows a requirement for a 50-amp 208 VAC receptacle. For this calculation, we will use 21 amps.
9bKM. 30Amps to Watts Conversion. As can be concluded from the formulas, in order to convert the units the voltage must be known, too. Supposed the PF is 0.5, and assumed the voltage is 110 V, we obtain these result: DC: P = 30 A Ã 110 V = 3300 W. AC, Single Phase: P = 30 A Ã 0.5 Ã 110 V AC2= 1650 W. AC, Three Phase, Line to Line Voltage: AC2P
SkaiÄiavimaspagal linijos ir linijos ÄŊtampÄ
. FazÄs srovÄ I amperais (A) yra lygi 1000 kartÅģ didesnei galiai P kilovatais (kW), padalijant iÅĄ kvadratinÄs ÅĄaknies iÅĄ 3 kartÅģ didesnio galios koeficiento PF , eilutÄs iki linijos RMS ÄŊtampos V L-L voltais (V): I (A) = 1000 Ã P (kW) / ( â 3 Ã PF Ã V L-L (V) )
Mostresidential electrical systems are 120 volts, so your heater will draw 62.5 amps. However, if you have a 240-volt system, your heater will only draw 31.3 amps. A 7.5 kilowatt (kW) heater will draw about 31.25 amps when it is operating at full capacity. This means that the heater will require a circuit that can handle at least 31.25 amps.
Onaverage, an electric vehicle will gain 11-31 miles of driving range per hour of Level 2 charging depending on whether a 20, 30, or 40-amp breaker is used. Larger breakers for faster charge times can be professionally installed. Level 2 charging provides kW of power per hour, and an average EV will get 3-5 miles of range per kilowatt
Simpleto use Ohm's Law Calculator. Calculate Power, Current, Voltage or Resistance. Just enter 2 known values and the calculator will solve for the others.
Saywe need to find the amperage of 3-phase motor with a 0.95 power factor, efficiency of 80% (or 0.8), and runs on a 220-volt 5-kilowatt power source. We have to substitute the variables on our 3-phase current formula with these values to
5 kw to amps 220v
